protractor.
11. The perimeter of a rhombus is equal to the circumference of a circle. If each side of the
rhombus measures 11 cm, then find the radius of the circle.
2. A piece of thin wire in the form of an equilateral triangle of side 88 dm in hont int
Answers
1)★FIND:
the radius of the circle=? .
★GIVEN,
The perimeter of a rhombus is equal to the circumference of a circle.
➡️each side of the
rhombus =11 cm
★SOLUTION:
Perimeter of a rhombus = 4s
Perimeter of a rhombus = 4 ×11
➡️44cm
Now,
according to the given question.
Perimeter of the rhombus = Circumference of the circle
➡️ 2πr = 44 cm
➡️ 2(22/7)r = 44
➡️44r = 44×7
➡️r = 7
➡️r =7 cm
So, the radius of the circle is 7 cm.
2)★FIND:
Diameter of the wire =?
★GIVEN:
A piece of thin wire in the form of an equilateral triangle of side = 88 dm
(1 dm=10cm)
★SOLUTION:
Perimeter of triangle=perimeter of circle.
Perimeter of triangle =A+B+C
Perimeter of triangle =88dm+88dm+88dm
➡️264dm=2640cm
Perimeter of triangle = perimeter of circle.
Perimeter of circle =2πr=2640cm
2πr = 2640
2r = 2640/π
2r = 2640 × 7/22
2r = 840 cm = 84 dm
Hence, the diameter of the wire is 84dm.
Step-by-step explanation:
The perimeter of a rhombus is equal to the circumference of a circle.
➡️each side of the
rhombus =11 cm
★SOLUTION:
Perimeter of a rhombus = 4s
Perimeter of a rhombus = 4 ×11
➡️44cm
Now,
according to the given question.
Perimeter of the rhombus = Circumference of the circle
➡️ 2πr = 44 cm
➡️ 2(22/7)r = 44
➡️44r = 44×7
➡️r = 7
➡️r =7 cm
So, the radius of the circle is 7 cm.
2)★FIND:
Diameter of the wire =?
★GIVEN:
A piece of thin wire in the form of an equilateral triangle of side = 88 dm
(1 dm=10cm)
★SOLUTION:
Perimeter of triangle=perimeter of circle.
Perimeter of triangle =A+B+C
Perimeter of triangle =88dm+88dm+88dm
➡️264dm=2640cm
Perimeter of triangle = perimeter of circle.
Perimeter of circle =2πr=2640cm
2πr = 2640
2r = 2640/π
2r = 2640 × 7/22
2r = 840 cm = 84 dm
Hence, the diameter of the wire is 84dm.