Question

Prove :-
1 / sec A + tan A = sec A - tan A
Irrelevant answers 10 answers will be reported ​

Answer 1

To Prove :-

$\dfrac{1}{ \sec(a) + \tan(a) } = \sec(a) - \tan(a)$

Solution :-

Taking LHS

→ 1/( secA + tanA)

Multiplying and dividing by sec A - tanA

→ 1/( secA + tanA) × ( secA - tanA) / ( secA - tanA)

→ ( secA - tanA) / sec²A - tan²A

We know that 1 + tan² A = sec²A

→ sec²A - tan²A = 1

→ ( secA - tanA) / 1

→ ( secA - tanA) = LHS = RHS

Hence proved.

Answer 2

Answer:

Step-by-step explanation: