Math, asked by harshraj7529, 6 days ago

Prove :-
1 / sec A + tan A = sec A - tan A
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Answers

Answered by Anonymous
11

To Prove :-

 \dfrac{1}{ \sec(a)  +  \tan(a) }  =  \sec(a)  -  \tan(a)

Solution :-

Taking LHS

→ 1/( secA + tanA)

Multiplying and dividing by sec A - tanA

→ 1/( secA + tanA) × ( secA - tanA) / ( secA - tanA)

→ ( secA - tanA) / sec²A - tan²A

We know that 1 + tan² A = sec²A

→ sec²A - tan²A = 1

→ ( secA - tanA) / 1

( secA - tanA) = LHS = RHS

Hence proved.

Answered by mahirh91
2

Answer:

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