prove :
(1+sina-cosa)2=2(1+sina)(1-cosa)
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Answer:
the smallest group of atoms which has the overall symmetry of a crystal, and from which the entire lattice can be built up by repetition in three dimensions.
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(1−sinA+cosA)
2
=1+sin
2
A+cos
2
A−2sinA+2cosA−2sinAcosA
=2−2sinA+2cosA−2sinAcosA
Considering RHS:
2(1−sinA)(1+cosA)=2(1+cosA−sinA−sinAcosA)
=2+2cosA−2sinA−2sinAcosA
2−2sinA+2cosA−2sinAcosA=2+2cosA−2sinA−2sinAcosA
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