Prove: (1+ tan square theta)(1+ sin theta)(1 - sin theta) = 1
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To prove:
(1+tan²A)(1+sinA)(1-sinA)=1
★Formulas to be used,
•sec²A-tan²A=1→1+tan²A=sec²A
•sin²A+cos²A=1→1-sin²A=cos²A
•cosA=1/secA→cos²A=1/sec²A
Now,
LHS:
(1+tan²A)(1+sinA)(1-sinA)
=(1+tan²A)(1-sin²A)
=sec²Acos²A
=1
=RHS
Hence,proved
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