Prove that
tanA + secA - 1 / tanA - secA +1 =1+ sinA/cosA
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Simplification :-
(tanA - secA) - (sec2A - tan2A) ÷ tanA + 1 - secA
(tanA - secA) (1 - (secA - tanA)) ÷ tanA + 1 - secA
(tanA - secA) (1 - secA + tanA) ÷ tanA + 1 - secA
sec A + tan A
1 ÷ cosA + sinA ÷ cosA
1 + sinA/cosA
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