Question

prove (10,24,26) is a Pythagorean triplet.

plz don't give irrelevant answer irrelevant answers would be reported.... ​

Answer 1

Answer:

Pythagoras theorem states that,

${a}^{2} + {b}^{2} = {c}^{2}$

So,

$= > {(26)}^{2} = {(24)}^{2} + {(10)}^{2} \\ = > 676 = 576 + 100 \\ = > 676 = 676 \\ hence \: \: \: \: proved.$

Hope this answer helps you ^_^ !

Answer 2

$\huge\underline\mathbb{\red Q\pink{U}\purple{ES} \blue{T} \orange{IO}\green{N :}}$

Prove 10, 24, 26 is a Pythagorean triplet.

$\huge\underline\mathbb{\red S\pink{O}\purple{LU} \blue{T} \orange{IO}\green{N :}}$

★ Let,

• Hypotenuse (AC) = 26cm.
• Opposite (AB) = 10cm.
• Adjacent (BC) = 24 cm.

★ We know that,

$\tt\purple{ Pythagoras \: Theorem : (Hypotenuse)^{2} = (Opposite)^{2} + (Adjacent)^{2}}$

$\sf\:⟹ (AC)^{2} = (AB)^{2} + (BC)^{2}$

$\sf\:⟹ (26)^{2} = (10)^{2} + (24)^{2}$

$\sf\:⟹ 676 = 100 + 576$

$\sf\:⟹ 676 = 676$

↪ Therefore, RHS = LHS.

Hence, it is proved...