Question

prove 2 under root3 upon 5 ir irrational

Answer 1

Now c divdes both q and thus the contradiction arised and what we had assumed is worng so it is irrational
Hope it helps pls mark brillianiest

Answer 2

Solution :

Correction :

Prove that (2√3)/5 is a irrational number ?

Let (2√3 )/5 be a rational number

⇒ (2√3)/5 = a/b

Where a and b are Co-prime numbers

Rearranging it

⇒ (2√3)/5 = a/b

⇒ 2√3 = (5a)/b

(5a)/b is a rational as it is in the form of p/q

But as We Know √3 is a irrational number . Hence , our assumption is wrong

(5√3)/5 be a irrational number