Prove 3-5√2 is irration
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Let us assume that 3 -5√2 is a rational number.
So it can be written in the form a/b
3 - 5√2 = a/b
Here a and b are coprime numbers and b ≠ 0
Solving 3 - 5√2 = a/b we get,
=>5√2 = a/b + 3
=>5√2 = (a+3b)/b
=>√2= (a+3b)/5b
This shows (a+3b)/5b is a rational number. But we know that But √2 is an irrational number.
so it contradictory assumption.
Our assumption of 3 -5√2 is a rational number is incorrect.
3 -5√2 is an irrational number
Hence proved...…..
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