prove √3+√7 is an irrational
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Step-by-step explanation:
let
root 3 + root 7 be a rational no
then
root 3 + root 7 =r
squaring both sides
(root 3 + root 7)^2 = (r)^2
(a+b)^2=a^2 +2ab+b^2
so
3 +2root 21 +7 = r^2
root 21=r^2-10/ 2
prove root 21 as irrational
RHS IS PURELY RATIONAL
LHS IS PURELY IRRATIONAL
SO IRRATIONAL AND RATIONAL CANNOT BE EQUAL
HENCE contradiction arises
therefore root 3 +root 7 is irrational
HOPE IT IS HELPFUL TO YOU
THANKS
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