Prove 6+root 2 as irrational
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Let, 6 + √2 be a rational number.
We know that 6 is a rational number.
Also, we know that
Rational - Rational = rational
=> (6 + √2 ) - 6 = Rational number
=> 6 - 6 + √2 = √2 = Rational number
But, √2 is an irrational number.
So, here our supposition gets wrong.
Hence, 6 + √2 will be a rational number.
We know that 6 is a rational number.
Also, we know that
Rational - Rational = rational
=> (6 + √2 ) - 6 = Rational number
=> 6 - 6 + √2 = √2 = Rational number
But, √2 is an irrational number.
So, here our supposition gets wrong.
Hence, 6 + √2 will be a rational number.
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