prove 7+3 under root 3 is irrational number
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If the question is too number then you also do √3 is irrational then you will meet 4marks
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Heya
Here is your answer
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If we add, multiply, divide, subtract anything from any irrational number then the whole no. becomes irrational so we just have to prove √3 irrational
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Here is the process:
Let √3 is rational no. a/b where a and b are co-prime
cross multiplying √3 and a/b
a = √3b
Squaring both sides
a² = 3b² ⇒ Equation 1
a²/3 = b²
⇒3 divide a²
⇒3 divide a
Putting a = 3c in equation 1
(3c)² = 3b²
9c² = 3b²
3c² = b²
c² = b²/3
⇒3 divide b²
⇒3 divide b
3 divide both a and b and our assumption was wrong.
So we conclude that √3 is irrational and hence 7+3√3 is irrational
Hence Proved.
____________________________________________________________
Hope it helps! ^_^
Here is your answer
_____________________________________________________________
If we add, multiply, divide, subtract anything from any irrational number then the whole no. becomes irrational so we just have to prove √3 irrational
_____________________________________________________________
Here is the process:
Let √3 is rational no. a/b where a and b are co-prime
cross multiplying √3 and a/b
a = √3b
Squaring both sides
a² = 3b² ⇒ Equation 1
a²/3 = b²
⇒3 divide a²
⇒3 divide a
Putting a = 3c in equation 1
(3c)² = 3b²
9c² = 3b²
3c² = b²
c² = b²/3
⇒3 divide b²
⇒3 divide b
3 divide both a and b and our assumption was wrong.
So we conclude that √3 is irrational and hence 7+3√3 is irrational
Hence Proved.
____________________________________________________________
Hope it helps! ^_^
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