Math, asked by thecoolone, 10 months ago

prove (a^m/a^-n)^m-n x (a^n/a^-l)^n-l x (a^l/a^-m)^l-m=1

Answers

Answered by adith757
32

Hope this helps you uuuu

Attachments:
Answered by dk1876123
5

Step-by-step explanation:

(a^m+n)^m-n×(a^n+l)^n-l×(a^l+m)l-m=1

a^m^2-n^2×a^n^2-l^2×a^l^2-m^2=1

a^m^2-n^2+n^2-l^2+l^2-m^2=1

a^m^2-m^2-n^2+n^2-l^2+l^2=1

a^0=1

1=1

LHS=RHS.

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