Question

Prove a3+b3 formulae

Answer 1

Answer:

a³ + b³ = (a + b)(a² – ab + b²)

you know that

(a + b)³ = a³ + 3ab(a + b) + b³

then a³ + b³ = (a + b)³ – 3ab(a + b)

= (a + b)[(a + b)² – 3ab]

= (a + b)(a² + 2ab + b² – 3ab)

= (a + b)(a² – ab + b² )

Step-by-step explanation:

I think it's help you.

Please please please Mark as Brainliest.

Answer 2

Step-by-step explanation:

a³ + b³ = (a + b)(a² – ab + b²)

you know that

(a + b)³ = a³ + 3ab(a + b) + b³

then a³ + b³ = (a + b)³ – 3ab(a + b)

= (a + b)[(a + b)² – 3ab]

= (a + b)(a² + 2ab + b² – 3ab)

= (a + b)(a² – ab + b² )