prove ac=db
prove that ac=db
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angle AOC=DOB _(1) (Vertically opposite angles)
ACO=BDO=70 _(2)(GIVEN)
By angle addition property in triangle AOC
70+30+OAC=180
Angle OAC=80
Similarly in triangle DOB
Angle DBO=80
Thus OAC=DBO_(3)
Thus from 1 , 2 and 3
by AAA test
triangle AOC=triangle DOB
Thus
AC=DB
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