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Answer:
Given a+2b = 5 ----(1)
To prove:
a³+8b³+30ab=125
Explanation:
On cubeing equation (1) , we get
(a+2b)³ = 5³
=> a³+(2b)³+3×a×2b×(a+2b)=125
/we know the algebraic identity:
(x^3+y^3) = x^3+y^3 + 3xy (X+Y)
=> a³+8y³+6ab×5 = 125
/* From equation (1) , we get */
=> a³+8y³+30ab = 125
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