prove= angles opposite to equal sides of a triangle are equal
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Step-by-step explanation:
Let D be the point of intersection of this bisector of ∠A and BC. Therefore ,by construction ∠BAD = ∠CAD. So, ∠ABD = ∠ACD, since they are corresponding angles of congruent triangles. Hence, Proved that an angle opposite to equal sides of an isosceles triangle is equal
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