Prove any three noncollinear points lie on a circle
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This is what I think is proof:
Consider a triangle ABC, now make perpendicular bisectors of any two sides, let's say AB and CD. Mark point of intersection as M. Let mid point of AB be D and of BC be E. We can easily say that MA=MB=MB by proving some triangles congruent
Consider a triangle ABC, now make perpendicular bisectors of any two sides, let's say AB and CD. Mark point of intersection as M. Let mid point of AB be D and of BC be E. We can easily say that MA=MB=MB by proving some triangles congruent
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As we know that non colinear point does not lie on straight line it may lie on curved line
since circle have curved line thus we can say that non colinear point lie on circle
since circle have curved line thus we can say that non colinear point lie on circle
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