prove area of rectangle
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Consider the square with side x+y units
The square is divided in to 4 parts
Two rectangles and two squares
WKT area of 2 squares = x^2+y^2
We have to find area of rectangle
Let A be the area of rectangle
Clearly we can say that area of largest square is equal to sum of areas of 2 smaller squares and two rectangle
Then we get
(x+y) × (x+y) = x^2 +y^2 + 2A
x^2 + 2x + y^2 = x^2 + y^2 +2A
2xy = 2A
A = xy
THEREFORE IT IS PROVED
Hopes this will help you
The square is divided in to 4 parts
Two rectangles and two squares
WKT area of 2 squares = x^2+y^2
We have to find area of rectangle
Let A be the area of rectangle
Clearly we can say that area of largest square is equal to sum of areas of 2 smaller squares and two rectangle
Then we get
(x+y) × (x+y) = x^2 +y^2 + 2A
x^2 + 2x + y^2 = x^2 + y^2 +2A
2xy = 2A
A = xy
THEREFORE IT IS PROVED
Hopes this will help you
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