Math, asked by simranbodh26, 4 months ago

Prove btp theorem....​

Answers

Answered by aksganesh
2

Basic Proportionality Theorem Proof

Statement:

If a line is parallel to a side of a triangle which intersects the other sides into two distinct points, then the line divides those sides in proportion

Given:

In triangle ΔABC, as shown in the given figure. In this triangle, we draw a line PQ parallel to the side BC of ΔABC and intersecting the sides AB and AC in P and Q, respectively

To prove:

AP/PB =AQ/QC

Proof

Now the area of ∆APQ = 1/2 × AP × QN (Since, area of a triangle= 1/2× Base × Height)

Similarly, area of ∆PBQ= 1/2 × PB × QN

area of ∆APQ = 1/2 × AQ × PM

Also,area of ∆QCP = 1/2 × QC × PM ………… (1)

Now, if we find the ratio of the area of triangles ∆APQand ∆PBQ, we have

area of ΔAPQarea of ΔPBQ = 12 × AP × QN12 × PB × QN = APPB

Similarly, area of ΔAPQarea of ΔQCP = 12 × AQ × PM12 × QC × PM = AQQC ………..(2)

According to the property of triangles, the triangles drawn between the same parallel lines and on the same base have equal areas.

Therefore, we can say that ∆PBQ and QCP have the same area.

area of ∆PBQ = area of ∆QCP …………..(3)

Therefore, from the equations (1), (2) and (3) we can say that,

AP/PB = AQ/QC

Also, ∆ABC and ∆APQ fulfil the conditions for similar triangles, as stated above. Thus, we can say that ∆ABC ~∆APQ.

The MidPoint theorem is a special case of the basic proportionality theorem.

According to mid-point theorem, a line drawn joining the midpoints of the two sides of a triangle is parallel to the third side.

Consider an ∆ABC.

Mid-point Theorem

Conclusion

If P and Q are the mid-points of AB and AC, then PQ || BC.

If P and Q are points on AB and AC such that AP = PB = 1/2 (AB) and AQ = QC = 1/2 (AC), then PQ || BC

Hence, the basic proportionality theorem is proved.

Answered by Anonymous
9

\huge{\fcolorbox{cyan}{black}{\red{ANSWER:-}}}

Let us now state the Basic Proportionality Theorem which is as follows:

  • If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio.

  • Hence, the basic proportionality theorem is proved.

  • Hence, proved

Hope it helps..!!

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