prove by mathematical induction 41ⁿ-14ⁿ is a multiple of 27
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41ⁿ - 14ⁿ is a multiple of 27. Let P (k) be true for some natural number k, ... = 27 (41a + 14k ), which is a multiple of 27. Thus P (k + 1) is true, whenever P (k) is true.
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