): Prove by mathematical induction. For any integer n ≥1, x3n – y3n is divisible by x - y, where x and y are any two integers with x ≠ y.
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Answer:
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Given : . For any integer n ≥1,x³ⁿ - y³ⁿ is divisible by x - y,
To Find : Prove by mathematical induction
Solution:
x³ⁿ - y³ⁿ is divisible by x - y
n = 1
=> x³ - y³ = ( x - y) (x² + xy + y²)
Hence divisible by x - y
Assume that for n = a a ∈ Z holds true
x³ᵃ - y³ᵃ is divisible by x - y
Hence x³ᵃ - y³ᵃ = k(x - y)
=> x³ᵃ = k(x - y) + y³ᵃ
n = a + 1
=> x⁽³ᵃ⁺³⁾ - y⁽³ᵃ⁺³⁾
= x³x³ᵃ - y³y³ᵃ
=> x³ (k(x - y) + y³ᵃ) - y³y³ᵃ
= k x³.x - k x³y + x³ y³ᵃ - y³y³ᵃ
= k x³(x - y) + y³ᵃ(x³ - y³)
= k x³(x - y) + y³ᵃ( x - y) (x² + xy + y²)
= (x - y) ( k x³ + y³ᵃ (x² + xy + y²))
Hence divisible by x - y
QED
Hence proved
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