Question

Prove by mathematical induction that the sum of the
squares of first n natural numbers is n(n+1)(2n +1).​

Answer 1

Answer:

(n+1)(n(2n+1)

Step-by-step explanation:

n(n+1)(2n+1)

(n square +2)(2n+1)

(2n cube + n square +2n square+n)

(2n cube+3n square+n)