Question

Prove by vector method that line joining the mid points of the diagonals of a trapezium is parallel to the parallel sides and is half of the difference of the parallel sides. ​

Answer 1

Step-by-step explanation:

be the position vectors of A, B, C, D respectively. Let P be the mid-point of diagonal AC and Q be mid-point of diagonal BD. ∴ PQ is half of the difference of parallel sides. Hence the result.