Question

prove cos(90-theta)sec (90-theta)tan theta ÷cosec (90-theta)sin (90-theta)cot (90-theta) + tan (90-theta)÷cot theta = 1

Answer 1

(o-cos theta)(sec theta)(tan theta/1-1/sin theta)
(1-sin theta)(0-cot theta+)-tan theta/1/tan theta=1

((0-cos theta)(1/tan theta)(tan theta/1/sin theta)(1-sin theta)(0-1/tan theta)(tan theta/cot theta)=1

(-cos theta)(1/sin theta)(1-sin theta)(1/tan theta)(tan theta/cot theta)=1
(-cot theta)(1-sin theta)(tan theta)
(1/tan )(1-sin theta)(tan theta)
1-sin theta=1
sin theta=2

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