Question

Prove :-
cosA/
1 +sinA
+ tan A
=SecA

Answer 1

Step-by-step explanation:

=cos A/(1+sin A)+tan A

=cos A/(1+sinA)+sin A/cos A

=[cos²A+sin A(1+sin A)]/cos A.(1+sin A)

=(cos²A+sin A+sin²A)/cos A.(1+sin A)

=(1+sin A)/cos A(1+sin A)

=1/cos A

=sec A

=RHS