Math, asked by Anonymous, 1 year ago

Prove: (cosec theta-cot theta)^2=1-cos theta/1+cos theta.

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Answered by Anonymous
9

SOLUTION

Refer to the attached

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Answered by Anonymous
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Step-by-step explanation:

(cotθ-cosecθ)²

=cot²θ-2cotθcosecθ+cosec²θ

=cos²θ/sin²θ-2(cosθ/sinθ)(1/sinθ)+1/sin²θ

=(cos²θ-2cosθ+1)/sin²θ

=(1-cosθ)²/(1-cos²θ)

=(1-cosθ)²/(1+cosθ)(1-cosθ)

=(1-cosθ)/(1+cosθ)

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