Prove: (cosec theta-cot theta)^2=1-cos theta/1+cos theta.
Answers
Answered by
9
SOLUTION
Refer to the attached
hope it helps ✔️
Attachments:
Answered by
5
Step-by-step explanation:
(cotθ-cosecθ)²
=cot²θ-2cotθcosecθ+cosec²θ
=cos²θ/sin²θ-2(cosθ/sinθ)(1/sinθ)+1/sin²θ
=(cos²θ-2cosθ+1)/sin²θ
=(1-cosθ)²/(1-cos²θ)
=(1-cosθ)²/(1+cosθ)(1-cosθ)
=(1-cosθ)/(1+cosθ)
Similar questions