Math, asked by mk9717562724, 9 months ago

prove cot a - 1 + cosec a /cota+1 -cosec a= cot a + cosec a​

Answers

Answered by Anonymous
2

 \huge\mathbb\red{Answer:-}

cotA−cosA

  sinAcosA+cosAsinAcosA−cosA=cosA+cosAsinAcosA−cosAsinA

                             =cosA(1+sinA)cosA(1−sinA)

                        =sinA1+sinAsinAsinA1−cosAsinA   

                             =cosecA+1cosecA−1

Answered by pulakmath007
2

\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>

  \displaystyle \: \frac{CotA - 1 + CosecA}{CotA  + 1  - CosecA}

 =   \displaystyle \: \frac{CotA  + CosecA - 1}{CotA    - CosecA + 1}

 =   \displaystyle \: \frac{CotA  + CosecA - ( {Cosec}^{2}A -  {Cot}^{2}A)  }{CotA  + 1  - CosecA}

 =\frac{(CotA  + CosecA )-(CosecA  + CotA )(CosecA   -  CotA ) }{CotA  + 1  - CosecA}

 =   \frac{(CotA  + CosecA )(CotA  + 1  - CosecA)}{(CotA  + 1  - CosecA)}

 = (CotA  + CosecA)

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