Prove : (cotx+1) (coty+1)/ cotx.coty =2
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[tex]{cosx + 1} {cosy + 1} / cosx . cosy
(cosx/sinx +1)(cosy /siny +1) /cosx/sinx. cosy / siny
1+1
2
hence proved
(cosx/sinx +1)(cosy /siny +1) /cosx/sinx. cosy / siny
1+1
2
hence proved
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