Math, asked by kacharearyan16, 18 days ago

Prove: Diagonals of a rhombus are perpendicular bisectors of each other. (Theorem)

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Answered by mayanknagdali122993

Answer:

A rhombus is a geometric figure that lies in a plane. ... Its diagonals divide the figure into 4 congruent triangles. Its diagonals are perpendicular bisectors of eachother. If all of a rhombus' angles are right angles, then the rhombus is a square.

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Prove: Diagonals of a rhombus are perpendicular bisectors of each other. (Theorem)​

Answers

Prove: Diagonals of a rhombus are perpendicular bisectors of each other. (Theorem)