prove dimensionally that : v=u+at
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quation is v=u+at
dimensional formula of v=(M°LT^-1)
dimensional formula of u=(M°LT^-1)
dimensional formula of a=(M°LT^-2)
dimensional formula of t=(M°L°T)
LHS is the dimensional formula of v=(M°LT^-1)
RHS=dimensional formula of u+dimensional formula of a×dimensional formula of t=(M°LT^-1)+(M°LT^-2)×(M°L°T)
=(M°LT^-1)+(M°LT^-1)
=2(M°LT^-1)
2 is a dimensionless constant
dimensional formula of v=(M°LT^-1)
dimensional formula of u=(M°LT^-1)
dimensional formula of a=(M°LT^-2)
dimensional formula of t=(M°L°T)
LHS is the dimensional formula of v=(M°LT^-1)
RHS=dimensional formula of u+dimensional formula of a×dimensional formula of t=(M°LT^-1)+(M°LT^-2)×(M°L°T)
=(M°LT^-1)+(M°LT^-1)
=2(M°LT^-1)
2 is a dimensionless constant
Answered by
0
hey yar here is ur answer
To check the correctness of v = u + at, using dimensions
Dimensional formula of final velocity v = [LT-1]
Dimensional formula of initial velocity u = [LT-1]
Dimensional formula of acceleration x time, at = [LT-2 x T]
= [LT-1]
HOPE IT HELPS YOU MARK ME AS BRAINLEST FOLLOW ME
To check the correctness of v = u + at, using dimensions
Dimensional formula of final velocity v = [LT-1]
Dimensional formula of initial velocity u = [LT-1]
Dimensional formula of acceleration x time, at = [LT-2 x T]
= [LT-1]
HOPE IT HELPS YOU MARK ME AS BRAINLEST FOLLOW ME
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