Question

prove each angle of rectangle is 90

Answer 1

Solution:-
Let us consider a rectangle ABCD.
We know that the diagonals of a rectangle are equal. Therefore, AC = DB
In triangle ABC and triangle DCB,
AB = DC (Opposite sides of a parallelogram)
AC = DB
BC = CB (Common side)
Therefore, triangle ABC is congruent to triangle DCB.
And, angle ABC = angle DCB (CPCT)
And, angle ABC + angle DCB = 180° (Adjacent angles of a parallelogram are supplementary/Co interior angles)
Therefore, angle ABC = angle DCB = 90°
And, angle ABC = angle ADC = 90° and angle DCB = angle BAC = 90° (Opposite angles of a parallelogram are equal.)
Hence, each angle of a rectangle measures 90°
Hence proved.

Answer 2

Answer:

Hope this help

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