Prove for any positive integer n that n3 − n is divisible by 3.
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likewise
4^3-4=60 and is divisible by 3
and moreover n^3 -n is hence becomes divisible of 3
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n3-1=n(n2-1)=n(n-1)(n+1)
here. n-1 ,n ,n+1 are three consecutive numbers
so one of the factor multiple of 3
so n3 -1 is multiple of 3
so it is divisible by 3
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