Question

Prove

guys plz jaldi help karo...
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Answer 1

Answer:

pls mark as brainliest

Answer 2

Given equation :

$\implies \: y = \dfrac{ {m}^{3} {n}^{4} }{ 16 {p}^{2} }$

In order to make the calculation easier let us replace 16 as 2⁴ we get ,

$\implies \: y = \dfrac{ {m}^{3} {n}^{4} }{ {2}^{4} {p}^{2} }$

Imp formulas :

$\star \boxed{ \blue{log ab = log \: a + logb}}$

$\star \boxed{ \blue{log \dfrac{a}{b} = log \: a - logb}}$

$\star \boxed{ \blue{log {a}^{b} = b \: log \: a }}$

Solution :

we know that ,

$\implies \: y = \dfrac{ {m}^{3} {n}^{4} }{ {2}^{4} {p}^{2} }$

Now taking log on both the sides we get ,

$\implies \: log(y) = log( {m}^{3} ) + log( {n}^{4} ) - [ \: log( {2}^{4} ) + log( {p}^{2} ) ]$

$\implies \: log(y) = log( {m}^{3} ) + log( {n}^{4} ) - \: log( {2}^{4} ) - log( {p}^{2} )$

$\implies \: log(y) = 3 log( m ) + 4log( n ) - \: 4 log( 2) - 2 log (p)$

Rearrange the equation,

$\large\boxed{ \red{\: 3 log(m) + 4 log(n) = 4 log(2) + 2 log(p) + log(y) }}$

Hope this helps :D