Prove identity a^3 - b^3
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Step-by-step explanation:
→ a³−b³=(a−b)(a²+b²+ab)
→ Let try to derive this expansion from the expansion of (a−b)³
→ We have,
→ (a−b)³=a³−b³−3ab(a−b)
→ (a−b)³+3ab(a−b)=a³−b³
→ (a−b)[(a−b)²+3ab]=a³−b³
→ (a−b)[(a²−2ab+b²)+3ab]=a³−b³
→ (a−b)(a²+b²+ab)=a³−b³
→ Therefore,
→ a³−b³=(a−b)(a²+b²+ab)
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