Question

prove it ....3 one plz .....with steps

Answer 1

hope this helps you☺️☺️

Answer 2

CosA+SinA=​root2CosA

SinA=root2CosA-CosA

SinA=CosA(root2-1)

Multiply by (root2+1) on numerator as well as denominator

 

SinA=CosA(root2-1)(root2+1)  /   (root2+1) 

SinA=CosA(2-1)  /  (root2+1) 

SinA=CosA / (root2+1) 

CosA=SinA(root2+1) 

CosA=root2SinA+SinA

CosA-SinA=root2SinA

Thus Prooved