Math, asked by sakshi345, 1 year ago

prove it fasttttttttt

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Answers

Answered by shuklashit
1
x^(a-b)(a+b)×x^(b-c)(b+c)×x^(c-a)(c+a)=1
x^a^2-b^2×x^b^2-c^2×x^c^2-a^2=1
(x)^a^2-b^2+b^2-c^2+c^2-a^2=1
x^0=1
1=1
therefore l.h.s.=r.h.s.

Answered by dfgh4
1
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