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【7 points】

Answer 1

Hey !!!!

•°• tan π/12 × tan 5π/12 × tan7π/12 × tan 11π/12

= tan π/12 × tan (π/2 - π/12 ) × tan(π/2 + π/12) × tan(π - π/12 )

= tan π/12 × tan ( 90° - π/12) × tan(90° + π/12) × tan( 180° - π/12)

= tan π/12 ×cot π/12 × (- cot π/12 ) ×( - tan π/12 )

= 1 × 1 [•°• tan¢ × cot¢ = 1 ]

= > 1 RHS prooved

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Hope it helps you !!!!

@Rajukumar111

Answer 2

1

Explanation:

tan5π/12=cot(π/2-5π/12)=cotπ/12

=> tan7π/12=tan(π-7π/12)=-tan5π/12=-cotπ/12

=> tan7π/12=-tanπ/12

=> tanπ/12×cotπ/12×-cotπ/12×-tanπ/12

=> 1×1 after cancelling out