Math, asked by khushisps, 1 year ago

prove it: (secA-cosA)(cot A+tanA)=tanAsecA

Answers

Answered by 9552688731
3
LHS = (secA-cosA)(cot A+tanA)

LHS = (1/cosA - cosA)(cosA/sinA+ sinA/cosA)

LHS = (1-cos²A/cosA)(cos²A+sin²A/sinAcosA)

LHS = (sin²A/cosA)(1/sinAcosA)

LHS = (sinA×sinA/cosA)(1/sinAcosA)

(cancel sinA and sinA)

LHS = (sinA/cosA)(1/cosA)

LHS = tanAsecA

LHS = RHS

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