Question

prove it (sinA-cosA) ² = 1- sin2A

Answer 1

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$\bold{\underline{Question-}}$


prove it (sinA-cosA) ² = 1- sin2A


$\bold{\underline{Answer-}}$


LHS = (sinA - cos A) ²

= sin²A + cos²A - 2sinA cos A

= 1 - sin2A. [°•° sin2A = 2sinA cos A]


Hence, prove

Answer 2

Answer:

LHS, (sin 30° – cos 30°) ²

(1/2–√3/2) ²

1/2–3/2

2/2=1

RHS ,1– sin 2×30° = 60°

1– √3/2

1 –3/2

2/2 = 1

therefore it's right answer