Math, asked by khansouravkumar, 1 year ago

Prove it: tanA+secA-1/tanA-secA+1=1+sinA/cosA

Answers

Answered by sandy1816

1

Step-by-step explanation:

tanA+secA-1/tanA-secA+1

=(secA+tanA)-(sec²A-tan²A)/(tanA-secA+1)

=(secA+tanA)(1-secA+tanA)/(tanA-secA+1)

=secA+tanA

=1+sinA/cosA

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