Prove it...the following question.
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Hey here's your answer.hope it helps.
In Square relations cos^2+sin^2=1
Hence sin square+cos square=1
In Square relations cos^2+sin^2=1
Hence sin square+cos square=1
raj1132:
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LHS=Sin^2+cos^2
Sin^2O+cos^2O=1. As the formula is cos^2+sin^2=1
Hope it helps
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Answered by
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consider a right angle triangle abc as shown in the image attached
by Pythagoras theroem
(AC)^2=(BC)^2 +(AB)^2
divide LHS And RHS by (AC)^2
we get ,
1=(BC/AC)^2+(AB/AC)^2
(BC/AC) and (AB/AC) are sin and cos of Angle A respectively
therefore , (sin^2A)+(cos^2A)=1
by Pythagoras theroem
(AC)^2=(BC)^2 +(AB)^2
divide LHS And RHS by (AC)^2
we get ,
1=(BC/AC)^2+(AB/AC)^2
(BC/AC) and (AB/AC) are sin and cos of Angle A respectively
therefore , (sin^2A)+(cos^2A)=1
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