prove it this is so Important quickly
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LHS=
sin(90-¢)sin¢/tan –1{:•sin(90-¢)=cos¢
cos×sin¢/sin÷cos. –1 {:•tan=sin/cos}
cos^2¢–1
-(1-cos^2¢)
-sin2^¢ RHS proved
it is so easy
sin(90-¢)sin¢/tan –1{:•sin(90-¢)=cos¢
cos×sin¢/sin÷cos. –1 {:•tan=sin/cos}
cos^2¢–1
-(1-cos^2¢)
-sin2^¢ RHS proved
it is so easy
arbazhaider1:
thanks
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