prove it with trigonometric identities
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Your question has a slight error
TO PROVE :
sec²Φ+ cosec²Φ = (tanΦ + cotΦ)²
PROOF:
LHS:
As we know,
sec²Φ = 1 + tan²Φ
cosec²Φ = 1 + cot²Φ
Hence, we get
sec²Φ + cosec²Φ
= 1 + tan²Φ + 1 + cot²Φ
= 2 + tan²Φ + cot²Φ
= (tanΦ + cotΦ)²
(We can write it like that because (tanΦ×cotΦ = 1) So while expanding
(tanΦ + cotΦ)² we get,
tan²Φ + 2 tanΦcotΦ + cot²Φ
= tan²Φ + cot²Φ + 2)
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