prove K•E• = ½mv^2 By calculus method
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Answered by
1
Explanation:
The work done is accelerating an object is given by:
W
=
F
Δ
x
Where
F
is the force and
Δ
x
the displacement.
If the object started from rest and all of the work was converted to kinetic energy then this will be equal to the kinetic energy of the object:
K
=
F
Δ
x
Using Newton's 2nd law:
K
=
m
a
Δ
x
=
m
(
a
Δ
x
)
Now using the equation of motion:
2
a
Δ
x
=
v
2
−
v
2
0
→
a
Δ
x
=
v
2
2
−
v
2
0
2
Substitute this into the equation for kinetic energy to get:
K
=
m
(
v
2
2
−
v
2
0
2
)
If the object started from rest then the initial velocity will be:
v
0
=
0
so
K
simplifies to:
K
=
m
v
2
2
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