Math, asked by mdLovelu, 9 months ago

Prove (L.HS.=R.H.S)

(tanA+SinA) - (tanA-SinA)=2tanAcosA

Answers

Answered by diksharana1784

2

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Answered by krishnajha0706

1

Answer: PLZ MARK ME AS BRAINLIST

Step-by-step explanation:

LHS=(tanA+sinA)-(tanA-sinA)

=(sinA/cosA+sinA)-(sinA/cosA-sinA)

=(sinA+sinAcosA/cosA)-(sinA-sinAcosA/cosA)

=sinA+sinAcosA-sinA+sinAcosA/cosA

=2sinAcosA/cosA

=2tanAcosA

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