prove lhs is equal to rhs
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Step-by-step explanation:
LHS => 1/cosec A + cosec A/cosec A
=> sin A + 1
=> (sin A + 1)(sin A - 1)/(sin A - 1)
[multiply numerator and denominator by sinA-1]
=> (sin²A - 1)/(sin A - 1)
=> - cos²A/sin A - 1 [ sin²A- 1 = - cos²A ]
=> cos²A / 1 - sin A hence proved
[ multiply by -1 both Nr & Dr ]
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