Question

prove lhs is equal to rhs​

Answer 1

Step-by-step explanation:

LHS => 1/cosec A + cosec A/cosec A

=> sin A + 1

=> (sin A + 1)(sin A - 1)/(sin A - 1)

[multiply numerator and denominator by sinA-1]

=> (sin²A - 1)/(sin A - 1)

=> - cos²A/sin A - 1 [ sin²A- 1 = - cos²A ]

=> cos²A / 1 - sin A hence proved

[ multiply by -1 both Nr & Dr ]