Question

prove
LHS =RHS who will give first answer I will make him brainliest​

Answer 1

Answer:

Step-by-step explanation:

Here it is

Now please thank and mark brainilest

Answer 2

Answer:

hi,

here's your answer

Step-by-step explanation:

$\frac{1+sec}{sec} = \frac{sin^{2} }{1-cos}$

as sec = 1/cos we can write,

$\frac{1+\frac{1}{cos} }{\frac{1}{cos} }$

lets take lcm of the numerator,

$\frac{\frac{cos+1}{cos} }{\frac{1}{cos} }$

which is ,

cos+1     --------------(LHS)

now lets solve RHS,

$\frac{sin^{2} }{1-cos}$

as $sin^{2} = 1- cos^{2}$

lets substitute the value in RHS,

$\frac{1-cos^{2} }{1-cos}$

as numerator is in the form of $a^{2} - b^{2} = (a+b) (a-b)$ we get,

$\frac{(1+cos)(1-cos)}{1-cos}$

which on cancelling we get,

1+cos   -----------(RHS)

therefore LHS = RHS

Mark as brainliest if you are satisfied with my answer