prove log 162+log76-log57-log27=3log2
Answers
Answered by
3
Step-by-step explanation:
log162+log76-(log57+log27)
log a + log b = log ab
log 162×76 - (log 57×27)
loga-logb = log (a/b)
log 162×76/(57×27)
log 8
= 3 log2
hope this helps
Similar questions