Question

prove log 32 base 2 =5 using formula log mn base a = log m base a+ log n base a​

Answer 1

Answer:

$log_{2}(32) = \\ \frac{ log(32) }{ log(2) } = \\ \frac{ log( {2}^{5} ) }{ log(2) } = \\ \frac{5 log(2) }{ log(2) } \\ = 5$

Answer 2

Answer:

this is correct.............................