Math, asked by riyanishad14, 10 months ago

What is least no that is divisible by all the numbers from 1 to 5

Answers

Answered by amitj4056
1

Answer:

60

Step-by-step explanation:

the ans will be the LCM of {1,2,3,4,5}

The steps would be as follows

LCM (1,2) = 2

LCM (2,3) = 6

LCM (6,4) = 12

LCM (12,5) = 60

Answered by anna5purna6
0

Answer:

Here,

2 - 1 = 1

3 - 2 = 1

4 - 3 = 1

5 - 4 = 1

6 - 5 = 1

That is, if we subtract 1 from the number divisible by 2, 3, 4, 5, 6, we get the required number.

The smallest number divisible by 2, 3, 4, 5, 6 will be the LCM of 2, 3, 4, 5, 6.

LCM of 2,3, 4, 5, 6 is

      2|2,3,4,5,6

     3|1,3,2,53

    2|1,1,2,5,1

    5|1,1,1,5,1

    1|1,1,1,1,1

The smallest no. divisible by 2,3,4,5 and 6

=LCM(2,3,4,5&6)

=2*3*2*5

=60

So, the required nos. which leaves a remainder of 1,2,3,4,5

=LCM of (2,3,4,5,6)-1

=59    

HOPE IT HELPS (n_n)

Step-by-step explanation:

Similar questions