What is least no that is divisible by all the numbers from 1 to 5
Answers
Answered by
1
Answer:
60
Step-by-step explanation:
the ans will be the LCM of {1,2,3,4,5}
The steps would be as follows
LCM (1,2) = 2
LCM (2,3) = 6
LCM (6,4) = 12
LCM (12,5) = 60
Answered by
0
Answer:
Here,
2 - 1 = 1
3 - 2 = 1
4 - 3 = 1
5 - 4 = 1
6 - 5 = 1
That is, if we subtract 1 from the number divisible by 2, 3, 4, 5, 6, we get the required number.
The smallest number divisible by 2, 3, 4, 5, 6 will be the LCM of 2, 3, 4, 5, 6.
LCM of 2,3, 4, 5, 6 is
2|2,3,4,5,6
3|1,3,2,53
2|1,1,2,5,1
5|1,1,1,5,1
1|1,1,1,1,1
The smallest no. divisible by 2,3,4,5 and 6
=LCM(2,3,4,5&6)
=2*3*2*5
=60
So, the required nos. which leaves a remainder of 1,2,3,4,5
=LCM of (2,3,4,5,6)-1
=59
HOPE IT HELPS (n_n)
Step-by-step explanation:
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